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11311034243023 = 59191712444797
BaseRepresentation
bin1010010010011000111000…
…1011011001011111001111
31111001022202102110022220001
42210212032023121133033
52440304444231234043
640020114542505131
72245123654501504
oct244461613313717
944038672408801
1011311034243023
113670a89a52319
1213281a25951a7
1364081a2a9638
142b1657d3d4ab
1514935c91d74d
hexa498e2d97cf

11311034243023 has 4 divisors (see below), whose sum is σ = 11502746687880. Its totient is φ = 11119321798168.

The previous prime is 11311034242999. The next prime is 11311034243027. The reversal of 11311034243023 is 32034243011311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11311034243023 - 29 = 11311034242511 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11311034242982 and 11311034243000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311034243027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95856222340 + ... + 95856222457.

It is an arithmetic number, because the mean of its divisors is an integer number (2875686671970).

Almost surely, 211311034243023 is an apocalyptic number.

11311034243023 is a deficient number, since it is larger than the sum of its proper divisors (191712444857).

11311034243023 is an equidigital number, since it uses as much as digits as its factorization.

11311034243023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 191712444856.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 11311034243023 its reverse (32034243011311), we get a palindrome (43345277254334).

The spelling of 11311034243023 in words is "eleven trillion, three hundred eleven billion, thirty-four million, two hundred forty-three thousand, twenty-three".

Divisors: 1 59 191712444797 11311034243023