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11311055031 = 341197466801
BaseRepresentation
bin10101000100011000…
…10000000010110111
31002012021202010112010
422202030100002313
5141131112230111
65110215055303
7550204244553
oct124214200267
932167663463
1011311055031
114884883071
122238071533
1310b34c6293
14794320863
15463033aa6
hex2a23100b7

11311055031 has 16 divisors (see below), whose sum is σ = 15527701728. Its totient is φ = 7319424000.

The previous prime is 11311055027. The next prime is 11311055059. The reversal of 11311055031 is 13055011311.

It is not a de Polignac number, because 11311055031 - 22 = 11311055027 is a prime.

It is a super-2 number, since 2×113110550312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11311054989 and 11311055007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311055071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 209170 + ... + 257631.

It is an arithmetic number, because the mean of its divisors is an integer number (970481358).

Almost surely, 211311055031 is an apocalyptic number.

11311055031 is a deficient number, since it is larger than the sum of its proper divisors (4216646697).

11311055031 is a wasteful number, since it uses less digits than its factorization.

11311055031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 467042.

The product of its (nonzero) digits is 225, while the sum is 21.

Adding to 11311055031 its reverse (13055011311), we get a palindrome (24366066342).

The spelling of 11311055031 in words is "eleven billion, three hundred eleven million, fifty-five thousand, thirty-one".

Divisors: 1 3 41 123 197 591 8077 24231 466801 1400403 19138841 57416523 91959797 275879391 3770351677 11311055031