Base | Representation |
---|---|
bin | 11001101101111110110101… |
… | …100100100011110101101001 |
3 | 112211111022021202201100210022 |
4 | 121231332311210203311221 |
5 | 104311202322030001413 |
6 | 1040322251452530225 |
7 | 32553000162305330 |
oct | 3155766544436551 |
9 | 484438252640708 |
10 | 113111010000233 |
11 | 3304a123390113 |
12 | 10829808480975 |
13 | 4b1642662a11b |
14 | 1dd086020cd17 |
15 | d12424a58608 |
hex | 66dfb5923d69 |
113111010000233 has 8 divisors (see below), whose sum is σ = 129277228012800. Its totient is φ = 96946667562240.
The previous prime is 113111010000227. The next prime is 113111010000301. The reversal of 113111010000233 is 332000010111311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113111010000233 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (113111010000433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 468764408 + ... + 469005641.
It is an arithmetic number, because the mean of its divisors is an integer number (16159653501600).
Almost surely, 2113111010000233 is an apocalyptic number.
It is an amenable number.
113111010000233 is a deficient number, since it is larger than the sum of its proper divisors (16166218012567).
113111010000233 is an equidigital number, since it uses as much as digits as its factorization.
113111010000233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 937787287.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113111010000233 its reverse (332000010111311), we get a palindrome (445111020111544).
The spelling of 113111010000233 in words is "one hundred thirteen trillion, one hundred eleven billion, ten million, two hundred thirty-three", and thus it is an aban number.
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