Base | Representation |
---|---|
bin | 1010010010011001001000… |
… | …1011010001010010101001 |
3 | 1111001022221002200002220001 |
4 | 2210212102023101102221 |
5 | 2440310113414141223 |
6 | 40020125340303001 |
7 | 2245125430564336 |
oct | 244462213212251 |
9 | 44038832602801 |
10 | 11311101318313 |
11 | 36710138a5a45 |
12 | 1328200b41a61 |
13 | 64082b162b64 |
14 | 2b1662bdd98d |
15 | 14936376c9ad |
hex | a49922d14a9 |
11311101318313 has 2 divisors, whose sum is σ = 11311101318314. Its totient is φ = 11311101318312.
The previous prime is 11311101318311. The next prime is 11311101318359. The reversal of 11311101318313 is 31381310111311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8777490558489 + 2533610759824 = 2962683^2 + 1591732^2 .
It is a cyclic number.
It is not a de Polignac number, because 11311101318313 - 21 = 11311101318311 is a prime.
Together with 11311101318311, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11311101318311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655550659156 + 5655550659157.
It is an arithmetic number, because the mean of its divisors is an integer number (5655550659157).
Almost surely, 211311101318313 is an apocalyptic number.
It is an amenable number.
11311101318313 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311101318313 is an equidigital number, since it uses as much as digits as its factorization.
11311101318313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 28.
Adding to 11311101318313 its reverse (31381310111311), we get a palindrome (42692411429624).
The spelling of 11311101318313 in words is "eleven trillion, three hundred eleven billion, one hundred one million, three hundred eighteen thousand, three hundred thirteen".
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