Base | Representation |
---|---|
bin | 11001101101111110110110… |
… | …001011110110011101100010 |
3 | 112211111022022111002122120222 |
4 | 121231332312023312131202 |
5 | 104311202332144101010 |
6 | 1040322252501403042 |
7 | 32553000345664226 |
oct | 3155766613663542 |
9 | 484438274078528 |
10 | 113111020300130 |
11 | 3304a129185626 |
12 | 1082980ba09482 |
13 | 4b164287c5338 |
14 | 1dd0861730786 |
15 | d124258e0355 |
hex | 66dfb62f6762 |
113111020300130 has 32 divisors (see below), whose sum is σ = 207943239873600. Its totient is φ = 44289209460672.
The previous prime is 113111020300129. The next prime is 113111020300141. The reversal of 113111020300130 is 31003020111311.
It is a junction number, because it is equal to n+sod(n) for n = 113111020300099 and 113111020300108.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 625039520 + ... + 625220459.
It is an arithmetic number, because the mean of its divisors is an integer number (6498226246050).
Almost surely, 2113111020300130 is an apocalyptic number.
113111020300130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113111020300130 is a deficient number, since it is larger than the sum of its proper divisors (94832219573470).
113111020300130 is a wasteful number, since it uses less digits than its factorization.
113111020300130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1250260178.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113111020300130 its reverse (31003020111311), we get a palindrome (144114040411441).
The spelling of 113111020300130 in words is "one hundred thirteen trillion, one hundred eleven billion, twenty million, three hundred thousand, one hundred thirty".
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