Base | Representation |
---|---|
bin | 10000011101011011011… |
… | …011011111011001101101 |
3 | 11000010121000122101021202 |
4 | 100131123123133121231 |
5 | 122013003221111023 |
6 | 2223342551535245 |
7 | 144501653120654 |
oct | 20353333373155 |
9 | 4003530571252 |
10 | 1131110332013 |
11 | 3a6779326992 |
12 | 16327268a525 |
13 | 828811caa5c |
14 | 3ca6318019b |
15 | 1e651d02128 |
hex | 1075b6df66d |
1131110332013 has 2 divisors, whose sum is σ = 1131110332014. Its totient is φ = 1131110332012.
The previous prime is 1131110331997. The next prime is 1131110332021. The reversal of 1131110332013 is 3102330111311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1100438764324 + 30671567689 = 1049018^2 + 175133^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131110332013 - 24 = 1131110331997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131110332063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565555166006 + 565555166007.
It is an arithmetic number, because the mean of its divisors is an integer number (565555166007).
Almost surely, 21131110332013 is an apocalyptic number.
It is an amenable number.
1131110332013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131110332013 is an equidigital number, since it uses as much as digits as its factorization.
1131110332013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1131110332013 its reverse (3102330111311), we get a palindrome (4233440443324).
The spelling of 1131110332013 in words is "one trillion, one hundred thirty-one billion, one hundred ten million, three hundred thirty-two thousand, thirteen".
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