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11311103331223 is a prime number
BaseRepresentation
bin1010010010011001001001…
…0010111100101110010111
31111001022221020110101002021
42210212102102330232113
52440310114423044343
640020125451354011
72245125453650023
oct244462222745627
944038836411067
1011311103331223
113671014a50303
121328201752907
1364082b6b9127
142b16631a5383
15149363a190ed
hexa49924bcb97

11311103331223 has 2 divisors, whose sum is σ = 11311103331224. Its totient is φ = 11311103331222.

The previous prime is 11311103331181. The next prime is 11311103331271. The reversal of 11311103331223 is 32213330111311.

11311103331223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11311103331223 - 225 = 11311069776791 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11311173331223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655551665611 + 5655551665612.

It is an arithmetic number, because the mean of its divisors is an integer number (5655551665612).

Almost surely, 211311103331223 is an apocalyptic number.

11311103331223 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311103331223 is an equidigital number, since it uses as much as digits as its factorization.

11311103331223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11311103331223 its reverse (32213330111311), we get a palindrome (43524433442534).

The spelling of 11311103331223 in words is "eleven trillion, three hundred eleven billion, one hundred three million, three hundred thirty-one thousand, two hundred twenty-three".