11311110003113 has 4 divisors (see below), whose sum is σ = 11336642983248. Its totient is φ = 11285577022980.

The previous prime is 11311110003091. The next prime is 11311110003203. The reversal of 11311110003113 is 31130001111311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11311110003113 - 2¹⁰ = 11311110002089 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11311110003091 and 11311110003100.

It is not an unprimeable number, because it can be changed into a prime (11311110006113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12766489403 + ... + 12766490288.

It is an arithmetic number, because the mean of its divisors is an integer number (2834160745812).

Almost surely, 2^{11311110003113} is an apocalyptic number.

It is an amenable number.

11311110003113 is a deficient number, since it is larger than the sum of its proper divisors (25532980135).

11311110003113 is an equidigital number, since it uses as much as digits as its factorization.

11311110003113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25532980134.

The product of its (nonzero) digits is 27, while the sum is 17.

Adding to 11311110003113 its reverse (31130001111311), we get a palindrome (42441111114424).

The spelling of 11311110003113 in words is "eleven trillion, three hundred eleven billion, one hundred ten million, three thousand, one hundred thirteen".