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1131111001997 = 1398137489223
BaseRepresentation
bin10000011101011011011…
…110000010111110001101
311000010121001220102022222
4100131123132002332031
5122013003404030442
62223343014145125
7144501661611164
oct20353336027615
94003531812288
101131111001997
113a6779744299
121632729521a5
13828813a39b2
143ca632b63db
151e651dd58d2
hex1075b782f8d

1131111001997 has 4 divisors (see below), whose sum is σ = 1139248491360. Its totient is φ = 1122973512636.

The previous prime is 1131111001963. The next prime is 1131111002011. The reversal of 1131111001997 is 7991001111311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1131111001997 - 218 = 1131110739853 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131111001597) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4068744473 + ... + 4068744750.

It is an arithmetic number, because the mean of its divisors is an integer number (284812122840).

Almost surely, 21131111001997 is an apocalyptic number.

It is an amenable number.

1131111001997 is a deficient number, since it is larger than the sum of its proper divisors (8137489363).

1131111001997 is an equidigital number, since it uses as much as digits as its factorization.

1131111001997 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8137489362.

The product of its (nonzero) digits is 1701, while the sum is 35.

The spelling of 1131111001997 in words is "one trillion, one hundred thirty-one billion, one hundred eleven million, one thousand, nine hundred ninety-seven".

Divisors: 1 139 8137489223 1131111001997