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11311111123003 = 30013769114003
BaseRepresentation
bin1010010010011001001011…
…0000101011000000111011
31111001022221210010020101201
42210212102300223000323
52440310123421414003
640020130330355031
72245125610121416
oct244462260530073
944038853106351
1011311111123003
11367101939239a
12132820428ba77
136408301b6853
142b1664232b7d
15149364557b1d
hexa4992c2b03b

11311111123003 has 4 divisors (see below), whose sum is σ = 11314880240008. Its totient is φ = 11307342006000.

The previous prime is 11311111122979. The next prime is 11311111123021. The reversal of 11311111123003 is 30032111111311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11311111123003 - 233 = 11302521188411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11311111123033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1884554001 + ... + 1884560002.

It is an arithmetic number, because the mean of its divisors is an integer number (2828720060002).

Almost surely, 211311111123003 is an apocalyptic number.

11311111123003 is a deficient number, since it is larger than the sum of its proper divisors (3769117005).

11311111123003 is an equidigital number, since it uses as much as digits as its factorization.

11311111123003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3769117004.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 11311111123003 its reverse (30032111111311), we get a palindrome (41343222234314).

The spelling of 11311111123003 in words is "eleven trillion, three hundred eleven billion, one hundred eleven million, one hundred twenty-three thousand, three".

Divisors: 1 3001 3769114003 11311111123003