113111120313041 has 4 divisors (see below), whose sum is σ = 113618345068032. Its totient is φ = 112603895558052.

The previous prime is 113111120313031. The next prime is 113111120313089. The reversal of 113111120313041 is 140313021111311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113111120313041 - 2³⁰ = 113110046571217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113111120312998 and 113111120313016.

It is not an unprimeable number, because it can be changed into a prime (113111120313031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 253612377161 + ... + 253612377606.

It is an arithmetic number, because the mean of its divisors is an integer number (28404586267008).

Almost surely, 2^{113111120313041} is an apocalyptic number.

It is an amenable number.

113111120313041 is a deficient number, since it is larger than the sum of its proper divisors (507224754991).

113111120313041 is an equidigital number, since it uses as much as digits as its factorization.

113111120313041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 507224754990.

The product of its (nonzero) digits is 216, while the sum is 23.

Adding to 113111120313041 its reverse (140313021111311), we get a palindrome (253424141424352).

The spelling of 113111120313041 in words is "one hundred thirteen trillion, one hundred eleven billion, one hundred twenty million, three hundred thirteen thousand, forty-one".