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113111213033 = 7132514952113
BaseRepresentation
bin110100101010111110…
…1000010001111101001
3101210221220200222022102
41221111331002033221
53323122432304113
6123543525503145
711113000306250
oct1512575021751
9353856628272
10113111213033
1143a74370555
1219b08871ab5
13a887c4c970
145690499797
152e20308758
hex1a55f423e9

113111213033 has 16 divisors (see below), whose sum is σ = 139768465536. Its totient is φ = 89138016000.

The previous prime is 113111212987. The next prime is 113111213057. The reversal of 113111213033 is 330312111311.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113111213033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113111212996 and 113111213014.

It is not an unprimeable number, because it can be changed into a prime (113111213533) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2453216 + ... + 2498897.

It is an arithmetic number, because the mean of its divisors is an integer number (8735529096).

Almost surely, 2113111213033 is an apocalyptic number.

113111213033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

113111213033 is a deficient number, since it is larger than the sum of its proper divisors (26657252503).

113111213033 is a wasteful number, since it uses less digits than its factorization.

113111213033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4952384.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 113111213033 its reverse (330312111311), we get a palindrome (443423324344).

The spelling of 113111213033 in words is "one hundred thirteen billion, one hundred eleven million, two hundred thirteen thousand, thirty-three".

Divisors: 1 7 13 91 251 1757 3263 22841 4952113 34664791 64377469 450642283 1242980363 8700862541 16158744719 113111213033