Base | Representation |
---|---|
bin | 110100101010111110… |
… | …1000010011111000111 |
3 | 101210221220201000200002 |
4 | 1221111331002133013 |
5 | 3323122432322043 |
6 | 123543525511515 |
7 | 11113000312163 |
oct | 1512575023707 |
9 | 353856630602 |
10 | 113111214023 |
11 | 43a74371275 |
12 | 19b0887259b |
13 | a887c50252 |
14 | 5690499ca3 |
15 | 2e20308bb8 |
hex | 1a55f427c7 |
113111214023 has 4 divisors (see below), whose sum is σ = 113231418168. Its totient is φ = 112991009880.
The previous prime is 113111213983. The next prime is 113111214031. The reversal of 113111214023 is 320412111311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113111214023 - 226 = 113044105159 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113111213986 and 113111214004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113111214323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60100661 + ... + 60102542.
It is an arithmetic number, because the mean of its divisors is an integer number (28307854542).
Almost surely, 2113111214023 is an apocalyptic number.
113111214023 is a deficient number, since it is larger than the sum of its proper divisors (120204145).
113111214023 is an equidigital number, since it uses as much as digits as its factorization.
113111214023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 120204144.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 113111214023 its reverse (320412111311), we get a palindrome (433523325334).
The spelling of 113111214023 in words is "one hundred thirteen billion, one hundred eleven million, two hundred fourteen thousand, twenty-three".
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