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113111312101 is a prime number
BaseRepresentation
bin110100101010111110…
…1011010011011100101
3101210221220220000012121
41221111331122123211
53323122443441401
6123543531545541
711113001201134
oct1512575323345
9353856800177
10113111312101
1143a74428a27
1219b088bb2b1
13a887c85a98
1456904c391b
152e20327ca1
hex1a55f5a6e5

113111312101 has 2 divisors, whose sum is σ = 113111312102. Its totient is φ = 113111312100.

The previous prime is 113111312089. The next prime is 113111312123. The reversal of 113111312101 is 101213111311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111672930625 + 1438381476 = 334175^2 + 37926^2 .

It is a cyclic number.

It is not a de Polignac number, because 113111312101 - 29 = 113111311589 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113111312191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56555656050 + 56555656051.

It is an arithmetic number, because the mean of its divisors is an integer number (56555656051).

Almost surely, 2113111312101 is an apocalyptic number.

It is an amenable number.

113111312101 is a deficient number, since it is larger than the sum of its proper divisors (1).

113111312101 is an equidigital number, since it uses as much as digits as its factorization.

113111312101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 113111312101 its reverse (101213111311), we get a palindrome (214324423412).

The spelling of 113111312101 in words is "one hundred thirteen billion, one hundred eleven million, three hundred twelve thousand, one hundred one".