Base | Representation |
---|---|
bin | 110100101010111110… |
… | …1100001001111110011 |
3 | 101210221220221102111121 |
4 | 1221111331201033303 |
5 | 3323123000340034 |
6 | 123543532323111 |
7 | 11113001345416 |
oct | 1512575411763 |
9 | 353856842447 |
10 | 113111340019 |
11 | 43a744479a7 |
12 | 19b08913497 |
13 | a887c956c2 |
14 | 56904cdb7d |
15 | 2e203311b4 |
hex | 1a55f613f3 |
113111340019 has 2 divisors, whose sum is σ = 113111340020. Its totient is φ = 113111340018.
The previous prime is 113111339987. The next prime is 113111340053. The reversal of 113111340019 is 910043111311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113111340019 - 25 = 113111339987 is a prime.
It is a super-2 number, since 2×1131113400192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113111339975 and 113111340002.
It is not a weakly prime, because it can be changed into another prime (113111340619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56555670009 + 56555670010.
It is an arithmetic number, because the mean of its divisors is an integer number (56555670010).
Almost surely, 2113111340019 is an apocalyptic number.
113111340019 is a deficient number, since it is larger than the sum of its proper divisors (1).
113111340019 is an equidigital number, since it uses as much as digits as its factorization.
113111340019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 25.
The spelling of 113111340019 in words is "one hundred thirteen billion, one hundred eleven million, three hundred forty thousand, nineteen".
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