Base | Representation |
---|---|
bin | 110100101011000000… |
… | …0000101000100000101 |
3 | 101210221222012111221020 |
4 | 1221112000011010011 |
5 | 3323123133323023 |
6 | 123543554541353 |
7 | 11113010141601 |
oct | 1512600050405 |
9 | 353858174836 |
10 | 113112011013 |
11 | 43a74866041 |
12 | 19b08b97859 |
13 | a88816bc41 |
14 | 5690626501 |
15 | 2e20414de3 |
hex | 1a56005105 |
113112011013 has 8 divisors (see below), whose sum is σ = 150817828608. Its totient is φ = 75407100384.
The previous prime is 113112011009. The next prime is 113112011021. The reversal of 113112011013 is 310110211311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 113112011013 - 22 = 113112011009 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 113112010983 and 113112011001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113112011083) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 157081 + ... + 500897.
It is an arithmetic number, because the mean of its divisors is an integer number (18852228576).
Almost surely, 2113112011013 is an apocalyptic number.
It is an amenable number.
113112011013 is a deficient number, since it is larger than the sum of its proper divisors (37705817595).
113112011013 is a wasteful number, since it uses less digits than its factorization.
113112011013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 453483.
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 113112011013 its reverse (310110211311), we get a palindrome (423222222324).
The spelling of 113112011013 in words is "one hundred thirteen billion, one hundred twelve million, eleven thousand, thirteen".
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