Base | Representation |
---|---|
bin | 1010010010011001100000… |
… | …1011010110000001110100 |
3 | 1111001100012010010022120220 |
4 | 2210212120023112001310 |
5 | 2440310320203013022 |
6 | 40020143334254340 |
7 | 2245131062432034 |
oct | 244463013260164 |
9 | 44040163108526 |
10 | 11311202001012 |
11 | 3671065713391 |
12 | 132822a7b73b0 |
13 | 640845c85314 |
14 | 2b167232b8c4 |
15 | 14936c50985c |
hex | a49982d6074 |
11311202001012 has 24 divisors (see below), whose sum is σ = 26394860382912. Its totient is φ = 3770106993600.
The previous prime is 11311202001007. The next prime is 11311202001037. The reversal of 11311202001012 is 21010020211311.
It is a junction number, because it is equal to n+sod(n) for n = 11311202000982 and 11311202001000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36548664 + ... + 36856847.
It is an arithmetic number, because the mean of its divisors is an integer number (1099785849288).
Almost surely, 211311202001012 is an apocalyptic number.
11311202001012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11311202001012 is an abundant number, since it is smaller than the sum of its proper divisors (15083658381900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11311202001012 is a wasteful number, since it uses less digits than its factorization.
11311202001012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73418359 (or 73418357 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 11311202001012 its reverse (21010020211311), we get a palindrome (32321222212323).
The spelling of 11311202001012 in words is "eleven trillion, three hundred eleven billion, two hundred two million, one thousand, twelve".
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