Base | Representation |
---|---|
bin | 1010010010011001100010… |
… | …1011000101110011100101 |
3 | 1111001100012200210010110002 |
4 | 2210212120223011303211 |
5 | 2440310324320320143 |
6 | 40020144232511045 |
7 | 2245131223242635 |
oct | 244463053056345 |
9 | 44040180703402 |
10 | 11311210323173 |
11 | 367106a387a02 |
12 | 132823154b485 |
13 | 64084790a287 |
14 | 2b16734966c5 |
15 | 14936d1005b8 |
hex | a4998ac5ce5 |
11311210323173 has 2 divisors, whose sum is σ = 11311210323174. Its totient is φ = 11311210323172.
The previous prime is 11311210323151. The next prime is 11311210323221. The reversal of 11311210323173 is 37132301211311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9136461384964 + 2174748938209 = 3022658^2 + 1474703^2 .
It is a cyclic number.
It is not a de Polignac number, because 11311210323173 - 222 = 11311206128869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311210323073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655605161586 + 5655605161587.
It is an arithmetic number, because the mean of its divisors is an integer number (5655605161587).
Almost surely, 211311210323173 is an apocalyptic number.
It is an amenable number.
11311210323173 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311210323173 is an equidigital number, since it uses as much as digits as its factorization.
11311210323173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2268, while the sum is 29.
Adding to 11311210323173 its reverse (37132301211311), we get a palindrome (48443511534484).
The spelling of 11311210323173 in words is "eleven trillion, three hundred eleven billion, two hundred ten million, three hundred twenty-three thousand, one hundred seventy-three".
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