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113112130993 is a prime number
BaseRepresentation
bin110100101011000000…
…0100010010110110001
3101210221222102121111221
41221112000202112301
53323123201142433
6123544001305041
711113011151441
oct1512600422661
9353858377457
10113112130993
1143a749381a4
1219b09035181
13a8881b1734
145690658121
152e2043a72d
hex1a560225b1

113112130993 has 2 divisors, whose sum is σ = 113112130994. Its totient is φ = 113112130992.

The previous prime is 113112130991. The next prime is 113112131009. The reversal of 113112130993 is 399031211311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 91489310784 + 21622820209 = 302472^2 + 147047^2 .

It is a cyclic number.

It is not a de Polignac number, because 113112130993 - 21 = 113112130991 is a prime.

Together with 113112130991, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (113112130991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56556065496 + 56556065497.

It is an arithmetic number, because the mean of its divisors is an integer number (56556065497).

Almost surely, 2113112130993 is an apocalyptic number.

It is an amenable number.

113112130993 is a deficient number, since it is larger than the sum of its proper divisors (1).

113112130993 is an equidigital number, since it uses as much as digits as its factorization.

113112130993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4374, while the sum is 34.

The spelling of 113112130993 in words is "one hundred thirteen billion, one hundred twelve million, one hundred thirty thousand, nine hundred ninety-three".