Base | Representation |
---|---|
bin | 10101000100011001… |
… | …10111101100101101 |
3 | 1002012022001101022202 |
4 | 22202030313230231 |
5 | 141131132424303 |
6 | 5110222351245 |
7 | 550205522234 |
oct | 124214675455 |
9 | 32168041282 |
10 | 11311217453 |
11 | 48849840a8 |
12 | 223812b525 |
13 | 10b35521a3 |
14 | 794363b1b |
15 | 463066c88 |
hex | 2a2337b2d |
11311217453 has 2 divisors, whose sum is σ = 11311217454. Its totient is φ = 11311217452.
The previous prime is 11311217431. The next prime is 11311217501. The reversal of 11311217453 is 35471211311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10518963844 + 792253609 = 102562^2 + 28147^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11311217453 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311217413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655608726 + 5655608727.
It is an arithmetic number, because the mean of its divisors is an integer number (5655608727).
Almost surely, 211311217453 is an apocalyptic number.
It is an amenable number.
11311217453 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311217453 is an equidigital number, since it uses as much as digits as its factorization.
11311217453 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2520, while the sum is 29.
Adding to 11311217453 its reverse (35471211311), we get a palindrome (46782428764).
The spelling of 11311217453 in words is "eleven billion, three hundred eleven million, two hundred seventeen thousand, four hundred fifty-three".
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