11311240032401 has 4 divisors (see below), whose sum is σ = 11803033077312. Its totient is φ = 10819446987492.

The previous prime is 11311240032377. The next prime is 11311240032439. The reversal of 11311240032401 is 10423004211311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11311240032401 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (23), and also a Moran number because the ratio is a prime number: 491793044887 = 11311240032401 / (1 + 1 + 3 + 1 + 1 + 2 + 4 + 0 + 0 + 3 + 2 + 4 + 0 + 1).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11311240032601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245896522421 + ... + 245896522466.

It is an arithmetic number, because the mean of its divisors is an integer number (2950758269328).

Almost surely, 2^{11311240032401} is an apocalyptic number.

It is an amenable number.

11311240032401 is a deficient number, since it is larger than the sum of its proper divisors (491793044911).

11311240032401 is an equidigital number, since it uses as much as digits as its factorization.

11311240032401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 491793044910.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 11311240032401 its reverse (10423004211311), we get a palindrome (21734244243712).

The spelling of 11311240032401 in words is "eleven trillion, three hundred eleven billion, two hundred forty million, thirty-two thousand, four hundred one".