Base | Representation |
---|---|
bin | 11001101110000000001110… |
… | …011010011010011010111010 |
3 | 112211111110010122101020011012 |
4 | 121232000032122122122322 |
5 | 104311213400112344232 |
6 | 1040323055415433522 |
7 | 32553052131406064 |
oct | 3156001632323272 |
9 | 484443118336135 |
10 | 113112500512442 |
11 | 3304a81877aa92 |
12 | 10829b636858a2 |
13 | 4b16603379a02 |
14 | 1dd0962162734 |
15 | d124b082b9b2 |
hex | 66e00e69a6ba |
113112500512442 has 4 divisors (see below), whose sum is σ = 169668750768666. Its totient is φ = 56556250256220.
The previous prime is 113112500512423. The next prime is 113112500512457. The reversal of 113112500512442 is 244215005211311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 58872795925321 + 54239704587121 = 7672861^2 + 7364761^2 .
It is a junction number, because it is equal to n+sod(n) for n = 113112500512399 and 113112500512408.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28278125128109 + ... + 28278125128112.
Almost surely, 2113112500512442 is an apocalyptic number.
113112500512442 is a deficient number, since it is larger than the sum of its proper divisors (56556250256224).
113112500512442 is an equidigital number, since it uses as much as digits as its factorization.
113112500512442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56556250256223.
The product of its (nonzero) digits is 9600, while the sum is 32.
Adding to 113112500512442 its reverse (244215005211311), we get a palindrome (357327505723753).
The spelling of 113112500512442 in words is "one hundred thirteen trillion, one hundred twelve billion, five hundred million, five hundred twelve thousand, four hundred forty-two".
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