Base | Representation |
---|---|
bin | 1010010010011001111000… |
… | …1000010100010101100111 |
3 | 1111001100110002001020101112 |
4 | 2210212132020110111213 |
5 | 2440311021234332301 |
6 | 40020201303015235 |
7 | 2245133414343035 |
oct | 244463610242547 |
9 | 44040402036345 |
10 | 11311301870951 |
11 | 3671107026125 |
12 | 132825813a51b |
13 | 640860881864 |
14 | 2b16816c7555 |
15 | 1493761859bb |
hex | a499e214567 |
11311301870951 has 2 divisors, whose sum is σ = 11311301870952. Its totient is φ = 11311301870950.
The previous prime is 11311301870927. The next prime is 11311301870959. The reversal of 11311301870951 is 15907810311311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11311301870951 - 222 = 11311297676647 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11311301870899 and 11311301870908.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311301870959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655650935475 + 5655650935476.
It is an arithmetic number, because the mean of its divisors is an integer number (5655650935476).
Almost surely, 211311301870951 is an apocalyptic number.
11311301870951 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311301870951 is an equidigital number, since it uses as much as digits as its factorization.
11311301870951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22680, while the sum is 41.
The spelling of 11311301870951 in words is "eleven trillion, three hundred eleven billion, three hundred one million, eight hundred seventy thousand, nine hundred fifty-one".
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