113113100103 has 4 divisors (see below), whose sum is σ = 150817466808. Its totient is φ = 75408733400.

The previous prime is 113113100071. The next prime is 113113100119. The reversal of 113113100103 is 301001311311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113113100103 - 2⁵ = 113113100071 is a prime.

It is a super-2 number, since 2×113113100103² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113113100153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18852183348 + ... + 18852183353.

It is an arithmetic number, because the mean of its divisors is an integer number (37704366702).

Almost surely, 2^113113100103 is an apocalyptic number.

113113100103 is a deficient number, since it is larger than the sum of its proper divisors (37704366705).

113113100103 is an equidigital number, since it uses as much as digits as its factorization.

113113100103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37704366704.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 113113100103 its reverse (301001311311), we get a palindrome (414114411414).

The spelling of 113113100103 in words is "one hundred thirteen billion, one hundred thirteen million, one hundred thousand, one hundred three".