Base | Representation |
---|---|
bin | 10101000100011010… |
… | …01110010100011011 |
3 | 1002012022020002102101 |
4 | 22202031032110123 |
5 | 141131143410412 |
6 | 5110224344231 |
7 | 550206356326 |
oct | 124215162433 |
9 | 32168202371 |
10 | 11311310107 |
11 | 4884a37779 |
12 | 2238175077 |
13 | 10b3585406 |
14 | 7943897bd |
15 | 463084457 |
hex | 2a234e51b |
11311310107 has 2 divisors, whose sum is σ = 11311310108. Its totient is φ = 11311310106.
The previous prime is 11311310099. The next prime is 11311310119. The reversal of 11311310107 is 70101311311.
It is a weak prime.
It is an emirp because it is prime and its reverse (70101311311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11311310107 - 23 = 11311310099 is a prime.
It is not a weakly prime, because it can be changed into another prime (11311310807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655655053 + 5655655054.
It is an arithmetic number, because the mean of its divisors is an integer number (5655655054).
Almost surely, 211311310107 is an apocalyptic number.
11311310107 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311310107 is an equidigital number, since it uses as much as digits as its factorization.
11311310107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63, while the sum is 19.
Adding to 11311310107 its reverse (70101311311), we get a palindrome (81412621418).
The spelling of 11311310107 in words is "eleven billion, three hundred eleven million, three hundred ten thousand, one hundred seven".
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