Base | Representation |
---|---|
bin | 110100101011000010… |
… | …0010000000010100111 |
3 | 101210222001021001222122 |
4 | 1221112010100002213 |
5 | 3323123423321201 |
6 | 123544034220155 |
7 | 11113022345006 |
oct | 1512604200247 |
9 | 353861231878 |
10 | 113113104551 |
11 | 43a75442697 |
12 | 19b0942465b |
13 | a8884628c5 |
14 | 569082cc3d |
15 | 2e2057de1b |
hex | 1a561100a7 |
113113104551 has 8 divisors (see below), whose sum is σ = 114393627360. Its totient is φ = 111832795008.
The previous prime is 113113104547. The next prime is 113113104571. The reversal of 113113104551 is 155401311311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113113104551 - 22 = 113113104547 is a prime.
It is a super-3 number, since 3×1131131045513 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 113113104551.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113113104571) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1171715 + ... + 1264571.
It is an arithmetic number, because the mean of its divisors is an integer number (14299203420).
Almost surely, 2113113104551 is an apocalyptic number.
113113104551 is a deficient number, since it is larger than the sum of its proper divisors (1280522809).
113113104551 is an equidigital number, since it uses as much as digits as its factorization.
113113104551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106633.
The product of its (nonzero) digits is 900, while the sum is 26.
Adding to 113113104551 its reverse (155401311311), we get a palindrome (268514415862).
The spelling of 113113104551 in words is "one hundred thirteen billion, one hundred thirteen million, one hundred four thousand, five hundred fifty-one".
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