Base | Representation |
---|---|
bin | 11001101110000000110010… |
… | …110100000010110001111101 |
3 | 112211111111201012111221021020 |
4 | 121232000302310002301331 |
5 | 104311221122432224013 |
6 | 1040323240153054353 |
7 | 32553103225304535 |
oct | 3156006264026175 |
9 | 484444635457236 |
10 | 113113111211133 |
11 | 33050001475a50 |
12 | 1082a0b40b73b9 |
13 | 4b1669ca50197 |
14 | 1dd09bd2d24c5 |
15 | d124e925e623 |
hex | 66e032d02c7d |
113113111211133 has 16 divisors (see below), whose sum is σ = 164547353606976. Its totient is φ = 68545404131840.
The previous prime is 113113111211101. The next prime is 113113111211143. The reversal of 113113111211133 is 331112111311311.
It is a cyclic number.
It is not a de Polignac number, because 113113111211133 - 25 = 113113111211101 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113113111211143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 199627860 + ... + 200193677.
It is an arithmetic number, because the mean of its divisors is an integer number (10284209600436).
Almost surely, 2113113111211133 is an apocalyptic number.
It is an amenable number.
113113111211133 is a deficient number, since it is larger than the sum of its proper divisors (51434242395843).
113113111211133 is a wasteful number, since it uses less digits than its factorization.
113113111211133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 399830124.
The product of its digits is 162, while the sum is 24.
Adding to 113113111211133 its reverse (331112111311311), we get a palindrome (444225222522444).
The spelling of 113113111211133 in words is "one hundred thirteen trillion, one hundred thirteen billion, one hundred eleven million, two hundred eleven thousand, one hundred thirty-three".
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