Base | Representation |
---|---|
bin | 1010010010011001111010… |
… | …1100010010010111001011 |
3 | 1111001100110201210021200011 |
4 | 2210212132230102113023 |
5 | 2440311031143100133 |
6 | 40020202241052351 |
7 | 2245133560444066 |
oct | 244463654222713 |
9 | 44040421707604 |
10 | 11311311300043 |
11 | 3671111386367 |
12 | 132825b3270b7 |
13 | 6408628035c1 |
14 | 2b1682a5d8dd |
15 | 149376de96cd |
hex | a499eb125cb |
11311311300043 has 2 divisors, whose sum is σ = 11311311300044. Its totient is φ = 11311311300042.
The previous prime is 11311311300011. The next prime is 11311311300067. The reversal of 11311311300043 is 34000311311311.
11311311300043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11311311300043 - 25 = 11311311300011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11311311299987 and 11311311300023.
It is not a weakly prime, because it can be changed into another prime (11311311400043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655655650021 + 5655655650022.
It is an arithmetic number, because the mean of its divisors is an integer number (5655655650022).
Almost surely, 211311311300043 is an apocalyptic number.
11311311300043 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311311300043 is an equidigital number, since it uses as much as digits as its factorization.
11311311300043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 11311311300043 its reverse (34000311311311), we get a palindrome (45311622611354).
The spelling of 11311311300043 in words is "eleven trillion, three hundred eleven billion, three hundred eleven million, three hundred thousand, forty-three".
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