Base | Representation |
---|---|
bin | 11001101110000000110010… |
… | …111010111100011000100111 |
3 | 112211111111201022220211111012 |
4 | 121232000302322330120213 |
5 | 104311221123413114233 |
6 | 1040323240255532435 |
7 | 32553103246550201 |
oct | 3156006272743047 |
9 | 484444638824435 |
10 | 113113113019943 |
11 | 330500024a0a33 |
12 | 1082a0b482a11b |
13 | 4b166a023459a |
14 | 1dd09bd643771 |
15 | d124e94ba548 |
hex | 66e032ebc627 |
113113113019943 has 2 divisors, whose sum is σ = 113113113019944. Its totient is φ = 113113113019942.
The previous prime is 113113113019931. The next prime is 113113113020027. The reversal of 113113113019943 is 349910311311311.
It is a weak prime.
It is an emirp because it is prime and its reverse (349910311311311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113113113019943 - 220 = 113113111971367 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 113113113019943.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113113113019243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56556556509971 + 56556556509972.
It is an arithmetic number, because the mean of its divisors is an integer number (56556556509972).
Almost surely, 2113113113019943 is an apocalyptic number.
113113113019943 is a deficient number, since it is larger than the sum of its proper divisors (1).
113113113019943 is an equidigital number, since it uses as much as digits as its factorization.
113113113019943 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 41.
The spelling of 113113113019943 in words is "one hundred thirteen trillion, one hundred thirteen billion, one hundred thirteen million, nineteen thousand, nine hundred forty-three".
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