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113113113019943 is a prime number
BaseRepresentation
bin11001101110000000110010…
…111010111100011000100111
3112211111111201022220211111012
4121232000302322330120213
5104311221123413114233
61040323240255532435
732553103246550201
oct3156006272743047
9484444638824435
10113113113019943
11330500024a0a33
121082a0b482a11b
134b166a023459a
141dd09bd643771
15d124e94ba548
hex66e032ebc627

113113113019943 has 2 divisors, whose sum is σ = 113113113019944. Its totient is φ = 113113113019942.

The previous prime is 113113113019931. The next prime is 113113113020027. The reversal of 113113113019943 is 349910311311311.

It is a weak prime.

It is an emirp because it is prime and its reverse (349910311311311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113113113019943 - 220 = 113113111971367 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113113113019943.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113113113019243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56556556509971 + 56556556509972.

It is an arithmetic number, because the mean of its divisors is an integer number (56556556509972).

Almost surely, 2113113113019943 is an apocalyptic number.

113113113019943 is a deficient number, since it is larger than the sum of its proper divisors (1).

113113113019943 is an equidigital number, since it uses as much as digits as its factorization.

113113113019943 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26244, while the sum is 41.

The spelling of 113113113019943 in words is "one hundred thirteen trillion, one hundred thirteen billion, one hundred thirteen million, nineteen thousand, nine hundred forty-three".