Base | Representation |
---|---|
bin | 1010010010011001111010… |
… | …1100011001101101101101 |
3 | 1111001100110201211210222111 |
4 | 2210212132230121231231 |
5 | 2440311031200031112 |
6 | 40020202241444021 |
7 | 2245133560630636 |
oct | 244463654315555 |
9 | 44040421753874 |
10 | 11311311330157 |
11 | 36711113a6a53 |
12 | 132825b340611 |
13 | 640862814217 |
14 | 2b1682a6a88d |
15 | 149376e035a7 |
hex | a499eb19b6d |
11311311330157 has 2 divisors, whose sum is σ = 11311311330158. Its totient is φ = 11311311330156.
The previous prime is 11311311330131. The next prime is 11311311330197. The reversal of 11311311330157 is 75103311311311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5899681513476 + 5411629816681 = 2428926^2 + 2326291^2 .
It is a cyclic number.
It is not a de Polignac number, because 11311311330157 - 219 = 11311310805869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311311330197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655655665078 + 5655655665079.
It is an arithmetic number, because the mean of its divisors is an integer number (5655655665079).
Almost surely, 211311311330157 is an apocalyptic number.
It is an amenable number.
11311311330157 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311311330157 is an equidigital number, since it uses as much as digits as its factorization.
11311311330157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2835, while the sum is 31.
Adding to 11311311330157 its reverse (75103311311311), we get a palindrome (86414622641468).
The spelling of 11311311330157 in words is "eleven trillion, three hundred eleven billion, three hundred eleven million, three hundred thirty thousand, one hundred fifty-seven".
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