Base | Representation |
---|---|
bin | 11001101110000000110100… |
… | …000000010101100111001011 |
3 | 112211111111202121011001012212 |
4 | 121232000310000111213023 |
5 | 104311221143042224321 |
6 | 1040323242145455335 |
7 | 32553103560304025 |
oct | 3156006400254713 |
9 | 484444677131185 |
10 | 113113131211211 |
11 | 3305001179633a |
12 | 1082a0ba94154b |
13 | 4b166a3c33651 |
14 | 1dd09c1c1b015 |
15 | d124eadb055b |
hex | 66e0340159cb |
113113131211211 has 2 divisors, whose sum is σ = 113113131211212. Its totient is φ = 113113131211210.
The previous prime is 113113131211177. The next prime is 113113131211219. The reversal of 113113131211211 is 112112131311311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113113131211211 - 214 = 113113131194827 is a prime.
It is not a weakly prime, because it can be changed into another prime (113113131211219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56556565605605 + 56556565605606.
It is an arithmetic number, because the mean of its divisors is an integer number (56556565605606).
Almost surely, 2113113131211211 is an apocalyptic number.
113113131211211 is a deficient number, since it is larger than the sum of its proper divisors (1).
113113131211211 is an equidigital number, since it uses as much as digits as its factorization.
113113131211211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 108, while the sum is 23.
Adding to 113113131211211 its reverse (112112131311311), we get a palindrome (225225262522522).
The spelling of 113113131211211 in words is "one hundred thirteen trillion, one hundred thirteen billion, one hundred thirty-one million, two hundred eleven thousand, two hundred eleven".
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