113113140314 has 4 divisors (see below), whose sum is σ = 169669710474. Its totient is φ = 56556570156.

The previous prime is 113113140307. The next prime is 113113140317. The reversal of 113113140314 is 413041311311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 413041311311 = 1753 ⋅235619687.

It can be written as a sum of positive squares in only one way, i.e., 113086256089 + 26884225 = 336283^2 + 5185^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 113113140314.

It is not an unprimeable number, because it can be changed into a prime (113113140317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28278285077 + ... + 28278285080.

Almost surely, 2^113113140314 is an apocalyptic number.

113113140314 is a deficient number, since it is larger than the sum of its proper divisors (56556570160).

113113140314 is an equidigital number, since it uses as much as digits as its factorization.

113113140314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56556570159.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 113113140314 its reverse (413041311311), we get a palindrome (526154451625).

The spelling of 113113140314 in words is "one hundred thirteen billion, one hundred thirteen million, one hundred forty thousand, three hundred fourteen".