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113113200001 = 146997695299
BaseRepresentation
bin110100101011000010…
…0100111010110000001
3101210222001102220220211
41221112010213112001
53323123434400001
6123544040234121
711113023223204
oct1512604472601
9353861386824
10113113200001
1143a754a837a
1219b0946b941
13a888497199
14569085593b
152e2059c351
hex1a56127581

113113200001 has 4 divisors (see below), whose sum is σ = 113120910000. Its totient is φ = 113105490004.

The previous prime is 113113199987. The next prime is 113113200007. The reversal of 113113200001 is 100002311311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113113200001 - 231 = 110965716353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113113200007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3832951 + ... + 3862348.

It is an arithmetic number, because the mean of its divisors is an integer number (28280227500).

Almost surely, 2113113200001 is an apocalyptic number.

It is an amenable number.

113113200001 is a deficient number, since it is larger than the sum of its proper divisors (7709999).

113113200001 is an equidigital number, since it uses as much as digits as its factorization.

113113200001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7709998.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 113113200001 its reverse (100002311311), we get a palindrome (213115511312).

The spelling of 113113200001 in words is "one hundred thirteen billion, one hundred thirteen million, two hundred thousand, one".

Divisors: 1 14699 7695299 113113200001