11311320011323 has 4 divisors (see below), whose sum is σ = 11368160815600. Its totient is φ = 11254479207048.

The previous prime is 11311320011311. The next prime is 11311320011351. The reversal of 11311320011323 is 32311002311311.

11311320011323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11311320011323 - 2⁵ = 11311320011291 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11311320011294 and 11311320011303.

It is not an unprimeable number, because it can be changed into a prime (11311320011923) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28420401840 + ... + 28420402237.

It is an arithmetic number, because the mean of its divisors is an integer number (2842040203900).

Almost surely, 2^{11311320011323} is an apocalyptic number.

11311320011323 is a deficient number, since it is larger than the sum of its proper divisors (56840804277).

11311320011323 is an equidigital number, since it uses as much as digits as its factorization.

11311320011323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56840804276.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 11311320011323 its reverse (32311002311311), we get a palindrome (43622322322634).

The spelling of 11311320011323 in words is "eleven trillion, three hundred eleven billion, three hundred twenty million, eleven thousand, three hundred twenty-three".