113113201303 has 4 divisors (see below), whose sum is σ = 113582550928. Its totient is φ = 112643851680.

The previous prime is 113113201261. The next prime is 113113201403. The reversal of 113113201303 is 303102311311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 303102311311 = 19603 ⋅15462037.

It is a cyclic number.

It is not a de Polignac number, because 113113201303 - 2²⁵ = 113079646871 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113113201403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234674451 + ... + 234674932.

It is an arithmetic number, because the mean of its divisors is an integer number (28395637732).

Almost surely, 2^113113201303 is an apocalyptic number.

113113201303 is a deficient number, since it is larger than the sum of its proper divisors (469349625).

113113201303 is an equidigital number, since it uses as much as digits as its factorization.

113113201303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 469349624.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 113113201303 its reverse (303102311311), we get a palindrome (416215512614).

The spelling of 113113201303 in words is "one hundred thirteen billion, one hundred thirteen million, two hundred one thousand, three hundred three".