Base | Representation |
---|---|
bin | 110100101011000010… |
… | …1000100101001001011 |
3 | 101210222001200000112122 |
4 | 1221112011010221023 |
5 | 3323124002220021 |
6 | 123544043001455 |
7 | 11113024233116 |
oct | 1512605045113 |
9 | 353861600478 |
10 | 113113320011 |
11 | 43a7557a55a |
12 | 19b0950928b |
13 | a8885099b3 |
14 | 569088757d |
15 | 2e205c2bab |
hex | 1a56144a4b |
113113320011 has 2 divisors, whose sum is σ = 113113320012. Its totient is φ = 113113320010.
The previous prime is 113113320007. The next prime is 113113320071. The reversal of 113113320011 is 110023311311.
It is a weak prime.
It is an emirp because it is prime and its reverse (110023311311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113113320011 - 22 = 113113320007 is a prime.
It is not a weakly prime, because it can be changed into another prime (113113320071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56556660005 + 56556660006.
It is an arithmetic number, because the mean of its divisors is an integer number (56556660006).
Almost surely, 2113113320011 is an apocalyptic number.
113113320011 is a deficient number, since it is larger than the sum of its proper divisors (1).
113113320011 is an equidigital number, since it uses as much as digits as its factorization.
113113320011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113113320011 its reverse (110023311311), we get a palindrome (223136631322).
The spelling of 113113320011 in words is "one hundred thirteen billion, one hundred thirteen million, three hundred twenty thousand, eleven".
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