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113113431133 = 523293973589
BaseRepresentation
bin110100101011000010…
…1011111110001011101
3101210222001212122222021
41221112011133301131
53323124014244013
6123544045220141
711113025205103
oct1512605376135
9353861778867
10113113431133
1143a75645a9a
1219b09561651
13a888548451
1456908b5c73
152e205e5a8d
hex1a5615fc5d

113113431133 has 8 divisors (see below), whose sum is σ = 113369810400. Its totient is φ = 112857205968.

The previous prime is 113113431121. The next prime is 113113431169. The reversal of 113113431133 is 331134311311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113113431133 - 213 = 113113422941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113113431098 and 113113431107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113113431113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1500303 + ... + 1573891.

It is an arithmetic number, because the mean of its divisors is an integer number (14171226300).

Almost surely, 2113113431133 is an apocalyptic number.

It is an amenable number.

113113431133 is a deficient number, since it is larger than the sum of its proper divisors (256379267).

113113431133 is an equidigital number, since it uses as much as digits as its factorization.

113113431133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 77051.

The product of its digits is 972, while the sum is 25.

Adding to 113113431133 its reverse (331134311311), we get a palindrome (444247742444).

The spelling of 113113431133 in words is "one hundred thirteen billion, one hundred thirteen million, four hundred thirty-one thousand, one hundred thirty-three".

Divisors: 1 523 2939 73589 1537097 38487047 216278071 113113431133