11311343143 has 4 divisors (see below), whose sum is σ = 11318171200. Its totient is φ = 11304515088.

The previous prime is 11311343117. The next prime is 11311343191. The reversal of 11311343143 is 34134311311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34134311311 = 67 ⋅509467333.

It is a cyclic number.

It is not a de Polignac number, because 11311343143 - 2⁵ = 11311343111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311143143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3411543 + ... + 3414856.

It is an arithmetic number, because the mean of its divisors is an integer number (2829542800).

Almost surely, 2^11311343143 is an apocalyptic number.

11311343143 is a deficient number, since it is larger than the sum of its proper divisors (6828057).

11311343143 is an equidigital number, since it uses as much as digits as its factorization.

11311343143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6828056.

The product of its digits is 1296, while the sum is 25.

Adding to 11311343143 its reverse (34134311311), we get a palindrome (45445654454).

The spelling of 11311343143 in words is "eleven billion, three hundred eleven million, three hundred forty-three thousand, one hundred forty-three".