Base | Representation |
---|---|
bin | 10000011101011100111… |
… | …011101010011111010101 |
3 | 11000010122210002020121101 |
4 | 100131130323222133111 |
5 | 122013031144341003 |
6 | 2223345252150101 |
7 | 144502410323062 |
oct | 20353473523725 |
9 | 4003583066541 |
10 | 1131135543253 |
11 | 3a6791586521 |
12 | 16327b008331 |
13 | 828864b7151 |
14 | 3ca66663c69 |
15 | 1e65413211d |
hex | 1075ceea7d5 |
1131135543253 has 2 divisors, whose sum is σ = 1131135543254. Its totient is φ = 1131135543252.
The previous prime is 1131135543191. The next prime is 1131135543257. The reversal of 1131135543253 is 3523455311311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 604534240324 + 526601302929 = 777518^2 + 725673^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131135543253 - 221 = 1131133446101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131135543257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565567771626 + 565567771627.
It is an arithmetic number, because the mean of its divisors is an integer number (565567771627).
Almost surely, 21131135543253 is an apocalyptic number.
It is an amenable number.
1131135543253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131135543253 is an equidigital number, since it uses as much as digits as its factorization.
1131135543253 is an evil number, because the sum of its binary digits is even.
The product of its digits is 81000, while the sum is 37.
The spelling of 1131135543253 in words is "one trillion, one hundred thirty-one billion, one hundred thirty-five million, five hundred forty-three thousand, two hundred fifty-three".
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