113114114 has 4 divisors (see below), whose sum is σ = 169671174. Its totient is φ = 56557056.

The previous prime is 113114081. The next prime is 113114117. The reversal of 113114114 is 411411311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 411411311 = 89 ⋅4622599.

It can be written as a sum of positive squares in only one way, i.e., 75082225 + 38031889 = 8665^2 + 6167^2 .

It is a junction number, because it is equal to n+sod(n) for n = 113114092 and 113114101.

It is not an unprimeable number, because it can be changed into a prime (113114117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28278527 + ... + 28278530.

Almost surely, 2^113114114 is an apocalyptic number.

113114114 is a deficient number, since it is larger than the sum of its proper divisors (56557060).

113114114 is an equidigital number, since it uses as much as digits as its factorization.

113114114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56557059.

The product of its digits is 48, while the sum is 17.

The square root of 113114114 is about 10635.5119293807. The cubic root of 113114114 is about 483.6214996087.

Adding to 113114114 its reverse (411411311), we get a palindrome (524525425).

The spelling of 113114114 in words is "one hundred thirteen million, one hundred fourteen thousand, one hundred fourteen".