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11311424013046 = 211251502685273
BaseRepresentation
bin1010010010011010010101…
…1010010000001011110110
31111001100202120212200211211
42210212211122100023312
52440311244021404141
640020221344552034
72245136426465323
oct244464532201366
944040676780754
1011311424013046
113671169a70303
12132829102261a
1364087cc787a1
142b16939ddb4a
15149381c60d81
hexa49a56902f6

11311424013046 has 8 divisors (see below), whose sum is σ = 16968644109144. Its totient is φ = 5655209310000.

The previous prime is 11311424013041. The next prime is 11311424013049. The reversal of 11311424013046 is 64031042411311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 11311424012999 and 11311424013017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311424013041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 251320135 + ... + 251365138.

It is an arithmetic number, because the mean of its divisors is an integer number (2121080513643).

Almost surely, 211311424013046 is an apocalyptic number.

11311424013046 is a deficient number, since it is larger than the sum of its proper divisors (5657220096098).

11311424013046 is a wasteful number, since it uses less digits than its factorization.

11311424013046 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 502696526.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 11311424013046 its reverse (64031042411311), we get a palindrome (75342466424357).

The spelling of 11311424013046 in words is "eleven trillion, three hundred eleven billion, four hundred twenty-four million, thirteen thousand, forty-six".

Divisors: 1 2 11251 22502 502685273 1005370546 5655712006523 11311424013046