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113119948853 is a prime number
BaseRepresentation
bin110100101011001111…
…0010111000000110101
3101210222112010210121022
41221112132113000311
53323132201330403
6123544441030525
711113134462152
oct1512636270065
9353875123538
10113119948853
1143a7929793a
1219b0b785445
13a8899baca2
1456916d1229
152e20e81d38
hex1a56797035

113119948853 has 2 divisors, whose sum is σ = 113119948854. Its totient is φ = 113119948852.

The previous prime is 113119948849. The next prime is 113119948957. The reversal of 113119948853 is 358849911311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 60906784849 + 52213164004 = 246793^2 + 228502^2 .

It is a cyclic number.

It is not a de Polignac number, because 113119948853 - 22 = 113119948849 is a prime.

It is a super-2 number, since 2×1131199488532 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113119948795 and 113119948804.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113119941853) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56559974426 + 56559974427.

It is an arithmetic number, because the mean of its divisors is an integer number (56559974427).

Almost surely, 2113119948853 is an apocalyptic number.

It is an amenable number.

113119948853 is a deficient number, since it is larger than the sum of its proper divisors (1).

113119948853 is an equidigital number, since it uses as much as digits as its factorization.

113119948853 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 933120, while the sum is 53.

The spelling of 113119948853 in words is "one hundred thirteen billion, one hundred nineteen million, nine hundred forty-eight thousand, eight hundred fifty-three".