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113120000133 = 375386666673
BaseRepresentation
bin110100101011001111…
…0100011100010000101
3101210222112020101221120
41221112132203202011
53323132210001013
6123544442104153
711113135064520
oct1512636434205
9353875211846
10113120000133
1143a79322418
1219b0b7ab059
13a889a0842a
145691705bb7
152e20e92123
hex1a567a3885

113120000133 has 8 divisors (see below), whose sum is σ = 172373333568. Its totient is φ = 64640000064.

The previous prime is 113120000099. The next prime is 113120000159. The reversal of 113120000133 is 331000021311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 113120000133 - 26 = 113120000069 is a prime.

It is a super-2 number, since 2×1131200001332 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113120000183) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2693333316 + ... + 2693333357.

It is an arithmetic number, because the mean of its divisors is an integer number (21546666696).

Almost surely, 2113120000133 is an apocalyptic number.

It is an amenable number.

113120000133 is a deficient number, since it is larger than the sum of its proper divisors (59253333435).

113120000133 is an equidigital number, since it uses as much as digits as its factorization.

113120000133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5386666683.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 113120000133 its reverse (331000021311), we get a palindrome (444120021444).

The spelling of 113120000133 in words is "one hundred thirteen billion, one hundred twenty million, one hundred thirty-three", and thus it is an aban number.

Divisors: 1 3 7 21 5386666673 16160000019 37706666711 113120000133