Base | Representation |
---|---|
bin | 110100101011001111… |
… | …0100011100010000101 |
3 | 101210222112020101221120 |
4 | 1221112132203202011 |
5 | 3323132210001013 |
6 | 123544442104153 |
7 | 11113135064520 |
oct | 1512636434205 |
9 | 353875211846 |
10 | 113120000133 |
11 | 43a79322418 |
12 | 19b0b7ab059 |
13 | a889a0842a |
14 | 5691705bb7 |
15 | 2e20e92123 |
hex | 1a567a3885 |
113120000133 has 8 divisors (see below), whose sum is σ = 172373333568. Its totient is φ = 64640000064.
The previous prime is 113120000099. The next prime is 113120000159. The reversal of 113120000133 is 331000021311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 113120000133 - 26 = 113120000069 is a prime.
It is a super-2 number, since 2×1131200001332 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113120000183) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2693333316 + ... + 2693333357.
It is an arithmetic number, because the mean of its divisors is an integer number (21546666696).
Almost surely, 2113120000133 is an apocalyptic number.
It is an amenable number.
113120000133 is a deficient number, since it is larger than the sum of its proper divisors (59253333435).
113120000133 is an equidigital number, since it uses as much as digits as its factorization.
113120000133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5386666683.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 113120000133 its reverse (331000021311), we get a palindrome (444120021444).
The spelling of 113120000133 in words is "one hundred thirteen billion, one hundred twenty million, one hundred thirty-three", and thus it is an aban number.
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