Base | Representation |
---|---|
bin | 10101000100011111… |
… | …10110110011101010 |
3 | 1002012100112011002122 |
4 | 22202033312303222 |
5 | 141131333001414 |
6 | 5110251231242 |
7 | 550215262343 |
oct | 124217666352 |
9 | 32170464078 |
10 | 11312000234 |
11 | 4885369227 |
12 | 2238448522 |
13 | 10b3767582 |
14 | 7944c90ca |
15 | 46316db8e |
hex | 2a23f6cea |
11312000234 has 4 divisors (see below), whose sum is σ = 16968000354. Its totient is φ = 5656000116.
The previous prime is 11312000213. The next prime is 11312000267. The reversal of 11312000234 is 43200021311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43200021311 = 499 ⋅86573189.
It can be written as a sum of positive squares in only one way, i.e., 9031651225 + 2280349009 = 95035^2 + 47753^2 .
It is a super-2 number, since 2×113120002342 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2828000057 + ... + 2828000060.
Almost surely, 211312000234 is an apocalyptic number.
11312000234 is a deficient number, since it is larger than the sum of its proper divisors (5656000120).
11312000234 is an equidigital number, since it uses as much as digits as its factorization.
11312000234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5656000119.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 11312000234 its reverse (43200021311), we get a palindrome (54512021545).
The spelling of 11312000234 in words is "eleven billion, three hundred twelve million, two hundred thirty-four", and thus it is an aban number.
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