Base | Representation |
---|---|
bin | 10000011101100000110… |
… | …010110011100111011011 |
3 | 11000010211021222202121001 |
4 | 100131200302303213123 |
5 | 122013144241031303 |
6 | 2223355524525431 |
7 | 144504125105236 |
oct | 20354062634733 |
9 | 4003737882531 |
10 | 1131200330203 |
11 | 3a6815106959 |
12 | 163298850877 |
13 | 82896a4bc18 |
14 | 3ca710ca41d |
15 | 1e659b7d31d |
hex | 10760cb39db |
1131200330203 has 8 divisors (see below), whose sum is σ = 1144939899600. Its totient is φ = 1117463395488.
The previous prime is 1131200330171. The next prime is 1131200330209. The reversal of 1131200330203 is 3020330021311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1131200330203 - 25 = 1131200330171 is a prime.
It is a super-2 number, since 2×11312003302032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1131200330209) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 212193 + ... + 1519021.
It is an arithmetic number, because the mean of its divisors is an integer number (143117487450).
Almost surely, 21131200330203 is an apocalyptic number.
1131200330203 is a deficient number, since it is larger than the sum of its proper divisors (13739569397).
1131200330203 is a wasteful number, since it uses less digits than its factorization.
1131200330203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1317341.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 1131200330203 its reverse (3020330021311), we get a palindrome (4151530351514).
The spelling of 1131200330203 in words is "one trillion, one hundred thirty-one billion, two hundred million, three hundred thirty thousand, two hundred three".
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