Search a number
-
+
11312023200000 = 2835553113787
BaseRepresentation
bin1010010010011100100100…
…0111111110000100000000
31111001102022100100112211020
42210213021013332010000
52440314010414400000
640020401031345440
72245160323500135
oct244471107760400
944042270315736
1011312023200000
113671447213336
121328419822280
1364094714b293
142b170d41458c
151493b966cba0
hexa49c91fe100

11312023200000 has 864 divisors, whose sum is σ = 38729149425792. Its totient is φ = 2929704960000.

The previous prime is 11312023199999. The next prime is 11312023200001. The reversal of 11312023200000 is 232021311.

It is an interprime number because it is at equal distance from previous prime (11312023199999) and next prime (11312023200001).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is not an unprimeable number, because it can be changed into a prime (11312023200001) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 14373599607 + ... + 14373600393.

It is an arithmetic number, because the mean of its divisors is an integer number (44825404428).

Almost surely, 211312023200000 is an apocalyptic number.

11312023200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11312023200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19364574712896).

11312023200000 is an abundant number, since it is smaller than the sum of its proper divisors (27417126225792).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11312023200000 is an frugal number, since it uses more digits than its factorization.

11312023200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 997 (or 963 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 11312023200000 its reverse (232021311), we get a palindrome (11312255221311).

The spelling of 11312023200000 in words is "eleven trillion, three hundred twelve billion, twenty-three million, two hundred thousand".