Base | Representation |
---|---|
bin | 10000011101100001000… |
… | …010010111011010101011 |
3 | 11000010211120122222122201 |
4 | 100131201002113122223 |
5 | 122013201312042003 |
6 | 2223400152201031 |
7 | 144504204553624 |
oct | 20354102273253 |
9 | 4003746588581 |
10 | 1131204409003 |
11 | 3a6817442369 |
12 | 16329a099177 |
13 | 82897849606 |
14 | 3ca7186ca4b |
15 | 1e65a1d6b1d |
hex | 107610976ab |
1131204409003 has 2 divisors, whose sum is σ = 1131204409004. Its totient is φ = 1131204409002.
The previous prime is 1131204409001. The next prime is 1131204409067. The reversal of 1131204409003 is 3009044021311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1131204409003 - 21 = 1131204409001 is a prime.
Together with 1131204409001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1131204409001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565602204501 + 565602204502.
It is an arithmetic number, because the mean of its divisors is an integer number (565602204502).
Almost surely, 21131204409003 is an apocalyptic number.
1131204409003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131204409003 is an equidigital number, since it uses as much as digits as its factorization.
1131204409003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 28.
The spelling of 1131204409003 in words is "one trillion, one hundred thirty-one billion, two hundred four million, four hundred nine thousand, three".
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