Base | Representation |
---|---|
bin | 10101000100100000… |
… | …01111010010010001 |
3 | 1002012100201020122002 |
4 | 22202100033102101 |
5 | 141131344203442 |
6 | 5110253323345 |
7 | 550216160555 |
oct | 124220172221 |
9 | 32170636562 |
10 | 11312100497 |
11 | 4885427595 |
12 | 2238496555 |
13 | 10b37a10b9 |
14 | 794513865 |
15 | 46318d732 |
hex | 2a240f491 |
11312100497 has 2 divisors, whose sum is σ = 11312100498. Its totient is φ = 11312100496.
The previous prime is 11312100463. The next prime is 11312100559. The reversal of 11312100497 is 79400121311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9588522241 + 1723578256 = 97921^2 + 41516^2 .
It is a cyclic number.
It is not a de Polignac number, because 11312100497 - 212 = 11312096401 is a prime.
It is not a weakly prime, because it can be changed into another prime (11312100797) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656050248 + 5656050249.
It is an arithmetic number, because the mean of its divisors is an integer number (5656050249).
Almost surely, 211312100497 is an apocalyptic number.
It is an amenable number.
11312100497 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312100497 is an equidigital number, since it uses as much as digits as its factorization.
11312100497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 29.
The spelling of 11312100497 in words is "eleven billion, three hundred twelve million, one hundred thousand, four hundred ninety-seven".
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