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11312103131 = 71985053407
BaseRepresentation
bin10101000100100000…
…01111111011011011
31002012100201101020122
422202100033323123
5141131344300011
65110253343455
7550216201340
oct124220177333
932170641218
1011312103131
11488542956a
122238497b8b
1310b37a2364
147945147c7
1546318e3db
hex2a240fedb

11312103131 has 8 divisors (see below), whose sum is σ = 13608545280. Its totient is φ = 9185767848.

The previous prime is 11312103113. The next prime is 11312103151. The reversal of 11312103131 is 13130121311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11312103131 is a prime.

It is a super-2 number, since 2×113121031312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11312103151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42526571 + ... + 42526836.

It is an arithmetic number, because the mean of its divisors is an integer number (1701068160).

Almost surely, 211312103131 is an apocalyptic number.

11312103131 is a deficient number, since it is larger than the sum of its proper divisors (2296442149).

11312103131 is an equidigital number, since it uses as much as digits as its factorization.

11312103131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85053433.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11312103131 its reverse (13130121311), we get a palindrome (24442224442).

The spelling of 11312103131 in words is "eleven billion, three hundred twelve million, one hundred three thousand, one hundred thirty-one".

Divisors: 1 7 19 133 85053407 595373849 1616014733 11312103131