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11312110113 = 35014775193
BaseRepresentation
bin10101000100100000…
…10001101000100001
31002012100201201211020
422202100101220201
5141131400010423
65110253440053
7550216230603
oct124220215041
932170651736
1011312110113
114885433837
1222384a0029
1310b37a55a5
14794517173
154631914e3
hex2a2411a21

11312110113 has 8 divisors (see below), whose sum is σ = 15083314848. Its totient is φ = 7541156064.

The previous prime is 11312110109. The next prime is 11312110133. The reversal of 11312110113 is 31101121311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11312110113 - 22 = 11312110109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11312110092 and 11312110101.

It is not an unprimeable number, because it can be changed into a prime (11312110133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 112845 + ... + 188037.

It is an arithmetic number, because the mean of its divisors is an integer number (1885414356).

Almost surely, 211312110113 is an apocalyptic number.

It is an amenable number.

11312110113 is a deficient number, since it is larger than the sum of its proper divisors (3771204735).

11312110113 is an equidigital number, since it uses as much as digits as its factorization.

11312110113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 125343.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 11312110113 its reverse (31101121311), we get a palindrome (42413231424).

The spelling of 11312110113 in words is "eleven billion, three hundred twelve million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 3 50147 75193 150441 225579 3770703371 11312110113